2 replies to this topic

[FrankRizzo]

I've got a boom that extends 6ft from the back of truck, with the
pivot pin 1ft up from the bed. I'd like to attach a hydraulic cylinder
1 foot up the boom from the pivot pin and have it extend down to the
base of the 1ft tall support that has the pivot pin for the boom (so
5ft from the tip of the boom to where the cylinder connects and then 1ft from
that connection to the pivot pin). I figure I'll have a maximum of
300 lbs to lift at any given time and will only need to raise the boom
up 15 degrees from horizontal. What sort of force will need to be
exerted by the hydraulic cylinder to maintain the 300lb load at the
end of my 6ft boom when it's angled 15-degrees up?

[ProfHawking]

Umm what? Are you sure this is the right place to ask?
Anyway, if you put all that in metric and draw a diagram ill take a look. If i can remember anything at all from Uni

Edited by ProfHawking, 02 April 2007 - 02:57 PM.

[BrightStar]

Lifting 300 lb on a 6 ft boom, 1 ft from the pivot point will require approx. 1800 lb of force, or 8200 Newtons (0.82 metric tonnes), plus an allowance for the weight of the boom and any dynamic loads (ie moving it...)

As ProfHawking says, a diagram would be helpful!

Edited by BrightStar, 02 April 2007 - 03:27 PM.