yep, I made the assumption of psi or tons-i on the gauge not tons full stop so the first part of my calculations werent needed.
however I still think you have something wrong in your post #8
3000kg = 6614pounds
the diameter of the ram piston is 48mm( = 1.889 inches), therefore surface area = 2.80 inch^2
this then presses on the tooling which is a cored cylinder (diameter 50mm (1.969 inches), with a central core of 22mm
(0.866 inches) bored out, so I calculate the area of the tooling as
Cylinder surface area = pi x (0.9845)^2 = 3.05 inch^2
Core surface area = pi x (0.433)^2 = 0.589 inch^ -
therefore Tooling surface area = 2.461 inch62
I wanted to see how this compared to typical rocket pressing pressures
so, 6614 / 2.80 = 2362 psi
so pressure on tooling is 2362 x 2.461 = 5813 psi
you have correctly converted kg to lb so we know the force generated by the ram (3000kg \ 6614lb) divided by the ram area gives the oil PSI (2362psi)
you don't really need this though as the oil is only acting on the ram generating force which we already know is 3000kg \ 6614lb
you then multiplied the OIL psi by your tooling which is wrong.
you should have divided the FORCE generated by the ram (3000kg \ 6614lb) by the tooling surface to give the PSI on the composition (as per the latter part of my calculation)
so I make it force/tooling area=psi on the comp so 6614 / 2.461 = 2687.52 PSI
AGAIN PLEASE anyone correct me if wrong?
